What is the Difference Between M2M and IoT

M2M represent the connections between machines to machines ,in M2M refers to the direct connection between two machines either using wired or wireless communication channels without human interaction , whereas IoT stand for Internet of Things, is based on a communication media likes sensors that can collect and analyze data in real-time. IoT is designed to be highly scalable because devices may also be included in the network and integrated into existing networks with minimal issues.

Difference Between M2M and IoT


  

    Basis
    IoT
    M2M
  

    

    protocol Using
    IoT has used internet protocols like FTP, Telnet, and HTTP.
    Communication technology and Traditional protocols are uses in M2M technology.
  

  

    Connection type used
    The connection is a point to point
    The connection is via Network and using various communication types.
  

    

    Scope
    It has a wide range of devices, yet the scope is large.
    It has a limited Scope for devices.
  

    

    Open API Support
    IoT technology supports Open API integrations.
    In M2M technology, there is no Open API support.
  

   

    Business Type
    IoT has Business to Consumer (B2C) and Business to Business (B2B).
    In M2M Business to Business (B2B) communication only.

Prove that (cotQ+ cosecQ -1) / (cotQ – cosecQ +1) = (1-cosQ) / sinQ?

Here we have to prove (cotQ+ cosecQ -1) / (cotQ – cosecQ +1) = (1-cosQ) / sinQ we will start with LHS (Left hand side ie (cotQ+ cosecQ -1) / (cotQ – cosecQ +1) and prove that it is equal to (1-cosQ) / sinQ Hence we will get LHS = RHS

Proof

Lets start with LHS of the equations
LHS = (cotQ+ cosecQ -1) / (cotQ – cosecQ +1)

= (cosQ/ sinQ + 1/sinQ – sinQ / sinQ) / (cosQ / sinQ – 1 / sinQ + sinQ / sinQ)

= (cosQ+ 1 – sinQ) / (cosQ – 1 + sinQ) * (cosQ + 1 – sinQ) / (cosQ + 1 – sinQ)

= (cosQ + 1 – sinQ) (cosQ + 1 – sinQ) / ( ((cosQ – 1 + sinQ) (cosQ + 1 – sinQ))

= (cosQ + 1 – sinQ)² / (cos²Q – (1 – sinQ)²)

= (cos²Q – 2 cosQ (1 – sinQ) + (1 – sinQ)²) / (cos²Q – 1 + 2 sinQ – sin²Q)

= (cos²Q – 2 cosQ + 2 sinQ cosQ + 1 – 2 sinQ + sin²Q) / (1 – sin² Q – 1 + 2 sinQ – sin²Q)
= (2 – 2 cosQ + 2 sinQ cosQ – 2 sinQ) / (2 sinQ – 2 sin²Q)
= 2 (1 – cosQ) (1 – sinQ) / (2 sinQ (1 – sinQ) )
= 1 – cosQ / sinQ
= RHS